((x^2)+4x)/3=300

Solution for ((x^2)+4x)/3=300 equation:

((x^2)+4x)/3=300

We move all terms to the left:

((x^2)+4x)/3-(300)=0

We multiply all the terms by the denominator


(x^2+4x)-300*3=0

We add all the numbers together, and all the variables

(x^2+4x)-900=0

We get rid of parentheses

x^2+4x-900=0

a = 1; b = 4; c = -900;
Δ = b2-4ac
Δ = 42-4·1·(-900)
Δ = 3616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3616}=\sqrt{16*226}=\sqrt{16}*\sqrt{226}=4\sqrt{226}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{226}}{2*1}=\frac{-4-4\sqrt{226}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{226}}{2*1}=\frac{-4+4\sqrt{226}}{2}
$